Passing an Entire Array to a Function
Passing an Entire Array to a Function
In C, we cannot pass an entire array as an argument to a function. When we passing the entire array into a function then we just passing the address of the zeroth element of the array to a function and obtained the other array element by increment in the value of pointer.
The address of the zero'th element (many a times called the base address) can also be passed by just passing the name of the array.
Thus, the following two statement are same :
& num[ 0 ] ;
num ;
Both point out the same element. Both indicate the zero'th element of the array ‘name’.
A Simple C Program to pass an array into a function.
# include < stdio.h >
int main( )
{
int marks[] = { 45, 64, 95, 40, 85, 79, 93 } ;
display( & marks[0], 7 ) ;
return ( 0 );
}
display( int *j, int n ) ;
{
for ( i = 1; i < n ; i ++ )
{
printf(" \n element = %d ", *j ) ;
j++ ;
}
}
The following all array pointer notation are same. All point out the same memory location.
num[i] ;
*( num + i ) ;
*( i + num ) ;
i[num] ;