C Program using structure to Print details of customers with less than given account balance
Write a C program to accept customer details such as: Account_no, Name, Balance using structure. Assume 3 customers in the bank. Write a function to print the account no. and name of each customer whose balance < 100 Rs.
\* C Program using structure to Print details of customers with less than given account balance *\
# include < stdio.h >
# include < conio.h >
struct bank
{
int acc_no ;
char name[20] ;
int bal ;
} b[3] ;
void check( struct bank b[], int n )
{
int i ;
printf("\n Customer Details whose Balance < 100 Rs. \n") ;
printf(" ----------------------------------------------\n") ;
for( i = 0 ; i < n ; i++ )
{
if( b[i].bal < 100 )
{
printf(" Account Number : %d\n",b[i].acc_no ) ;
printf(" Name : %s\n",b[i].name ) ;
printf(" Balance : %d\n",b[i].bal ) ;
printf(" ------------------------------\n") ;
}
}
}
int main( )
{
int i ;
for( i = 0 ; i < 3 ; i++ )
{
printf(" Enter Details of Customer %d\n", i+1 ) ;
printf(" ------------------------------\n") ;
printf(" Enter Account Number : ") ;
scanf("%d",&b[i].acc_no) ;
printf(" Enter Name : ") ;
scanf("%s",b[i].name) ;
printf(" Enter Balance : ") ;
scanf("%d",&b[i].bal) ;
printf(" ------------------------------\n") ;
}
check( b, 3 ) ;
return 0 ;
}
Output of Program :
